Readit NewsDeleted Comment
pksadiq commented on Wikipedia switches to CC BY-SA 4.0 license diff.wikimedia.org/2023/0... · Posted by u/skilled
Why every goddamn thing has to be exciting? Surely American organizational culture is becoming a parody of itself.
If anything, this reminds us that American non-profits are run just like corporations.
This specific change shall excite many as CC BY-SA 4.0 is one way GPLv3 compatible, but CC BY-SA 3.0 is not. Which means that free software developers can now embedded many Wikimedia contents in their GPLv3 applications. This seems not mentioned in the blog post though.
Deleted Comment
pksadiq commented on Fast midpoint between two integers without overflow lemire.me/blog/2022/12/06... · Posted by u/ibobev
Isn't (32 bit) INT_MAX 2^31-1 and INT_MIN -2^31, so this is an acceptable solution (since the decimal average is -0.5)?
> since the decimal average is -0.5
The C standard says: When integers are divided, the result of the / operator is the algebraic quotient with any fractional part discarded (This is often called ‘‘truncation toward zero’’).
So it should be 0 (as per C standard, not sure what C++ standard says)
pksadiq commented on Fast midpoint between two integers without overflow lemire.me/blog/2022/12/06... · Posted by u/ibobev
> Then the majority come up with (a / 2) + (b / 2) until they run the unit tests and realize it's wrong.
Seems like you can cover the corner case easily enough:
x/2 + y/2 + (x & y & 0x01)
> x/2 + y/2 + (x & y & 0x01)
This returns -1 for x = INT_MIN and y = INT_MAX were the answer should be 0 (for an example). so not a correct solution
pksadiq commented on Fast midpoint between two integers without overflow lemire.me/blog/2022/12/06... · Posted by u/ibobev
int mid(int x, int y) {
return (x/2 + y/2) + (1 & x & y);
}
edit: Actually, this fails on mid(INT_MIN, INT_MAX) and possibly other mixed sign values (returns: -1, expected: 0 (or -1 is okay?), where the precise answer is -0.5)
more edit: The C standard says: When integers are divided, the result of the / operator is the algebraic quotient with any fractional part discarded (This is often called ‘‘truncation toward zero’’).
So -1/2 should be 0.
https://github.com/zmwangx/ets
[0] https://www.sadiqpk.org/projects/tis